(3x^2)+3x=500

Solution for (3x^2)+3x=500 equation:

(3x^2)+3x=500

We move all terms to the left:

(3x^2)+3x-(500)=0

a = 3; b = 3; c = -500;
Δ = b2-4ac
Δ = 32-4·3·(-500)
Δ = 6009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{6009}}{2*3}=\frac{-3-\sqrt{6009}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{6009}}{2*3}=\frac{-3+\sqrt{6009}}{6}
$